If:
2 + 3 =8,
3 + 7 =27,
4 + 5 =32,
5 + 8 =60,
6 + 7 =72,
then:
7 + 8 = ?
Answer:
98
2+3=2*[3+(2-1)]=8
3+7=3*[7+(3-1)]=27
4+5=4*[5+(4-1)]=32
5+8=5*[8+(5-1)]=60
6+7=6*[7+(6-1)]=72
therefore:
7+8=7*[8+(7-1)]=98
x+y=x[y+(x-1)]=x^2+xy-x"
2 + 3 =8,
3 + 7 =27,
4 + 5 =32,
5 + 8 =60,
6 + 7 =72,
then:
7 + 8 = ?
Answer:
98
2+3=2*[3+(2-1)]=8
3+7=3*[7+(3-1)]=27
4+5=4*[5+(4-1)]=32
5+8=5*[8+(5-1)]=60
6+7=6*[7+(6-1)]=72
therefore:
7+8=7*[8+(7-1)]=98
x+y=x[y+(x-1)]=x^2+xy-x"
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