Monday, February 25, 2013
Find a 13-letter English Word
In the following puzzle, as in the previous post, starting from any letter, trace out a 13-letter English word by going along the lines without crossing any letter more than once.
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ANSWER: Breaststroker
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_______________________
ANSWER: Breaststroker
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Word Ladder: Chase to Catch!
In this word ladder, you should start from Chase and end to Catch by adding 8 words in between!
Note: A Word Ladder is a word game invented by Lewis Carroll. A word ladder puzzle begins with two words, and to solve the puzzle one must find a chain of other words to link the two, where at each step the words differ by altering a single letter [for more info visit http://en.wikipedia.org/wiki/Word_ladder].
Note: A Word Ladder is a word game invented by Lewis Carroll. A word ladder puzzle begins with two words, and to solve the puzzle one must find a chain of other words to link the two, where at each step the words differ by altering a single letter [for more info visit http://en.wikipedia.org/wiki/Word_ladder].
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ANSWER:
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ANSWER:
________________________
source: http://www.puzzlechoice.com
Sunday, February 24, 2013
Little Helpers
Santa is getting ready for Christmas - sorting presents, filling sacks and working out his route to make sure he can deliver all his wonderful presents to the children of the world in time for when they wake up Christmas morning. The trouble is, every year just before Christmas, the reindeer have nothing to do and mostly stand around getting rather bored. They are always asking if they can help but there's nothing they can do until Santa's ready to go.
?This year, Santa is prepared for them and he's set them a little challenge to help keep them busy. He's given them the following problem:
Five children from five different families living in five different counties of England have asked for a different gift each. From the clues, the reindeer have to work out who's who, where each child lives and what present each has asked for. The first reindeer to solve the problem gets an extra portion of Christmas pudding on Christmas Day!
1. Neither Cliff, nor Jennifer Feather (who does not live in Yorkshire), lives in Kent.
2. Young Crawford, who is neither Sarah nor Cliff, asked for the pony (a gift that Santa would have particular difficulty getting down the Crawford family's chimney!).
3. Young Rowlands is neither the child who lives in Yorkshire nor the child who has asked for a bicycle.
4. The gift due for delivery to Cornwall, which is not for the child surnamed Rowlands, is a computer.
5. Liz, who has asked for the painting set, is not from Kent. Her surname is not Jamison.
6. The child who lives in Essex has asked for a guitar. Alan lives in Cumbria.
Children’s first names: Alan, Cliff, Jennifer, Liz, Sarah
Children’s last names: Crawford, Feather, Jamison, Northey, Rowlands
Counties: Cornwall, Cumbria, Essex, Kent, Yorkshire
Presents: Bicycle, Computer, Guitar, Painting Set, Pony
?This year, Santa is prepared for them and he's set them a little challenge to help keep them busy. He's given them the following problem:
Five children from five different families living in five different counties of England have asked for a different gift each. From the clues, the reindeer have to work out who's who, where each child lives and what present each has asked for. The first reindeer to solve the problem gets an extra portion of Christmas pudding on Christmas Day!
1. Neither Cliff, nor Jennifer Feather (who does not live in Yorkshire), lives in Kent.
2. Young Crawford, who is neither Sarah nor Cliff, asked for the pony (a gift that Santa would have particular difficulty getting down the Crawford family's chimney!).
3. Young Rowlands is neither the child who lives in Yorkshire nor the child who has asked for a bicycle.
4. The gift due for delivery to Cornwall, which is not for the child surnamed Rowlands, is a computer.
5. Liz, who has asked for the painting set, is not from Kent. Her surname is not Jamison.
6. The child who lives in Essex has asked for a guitar. Alan lives in Cumbria.
Children’s first names: Alan, Cliff, Jennifer, Liz, Sarah
Children’s last names: Crawford, Feather, Jamison, Northey, Rowlands
Counties: Cornwall, Cumbria, Essex, Kent, Yorkshire
Presents: Bicycle, Computer, Guitar, Painting Set, Pony
Answer:
Name County Present Alan Crawford Cumbria Pony
Cliff Rowlands Essex Guitar
Jennifer Feather Cornwall Computer
Liz Northey Yorkshire Painting Set
Sarah Jamison Kent Bicycle
Saturday, February 23, 2013
Toward a Target
You can imagine an arrow in flight, toward a target. For the arrow to reach the target, the arrow must first travel half of the overall distance from the starting point to the target. Next, the arrow must travel half of the remaining distance.
For example, if the starting distance was 10m, the arrow first travels 5m, then 2.5m.
If you extend this concept further, you can imagine the resulting distances getting smaller and smaller. Will the arrow ever reach the target?
For example, if the starting distance was 10m, the arrow first travels 5m, then 2.5m.
If you extend this concept further, you can imagine the resulting distances getting smaller and smaller. Will the arrow ever reach the target?
Answer:
Yes.
Since the arrow does indeed hit the target, it must be true that 1/2 + 1/4 + 1/8 + ... = 1.
This is because the sum of an infinite series can be a finite number.
Room Rate
Three people check into a hotel. They pay £30 to the manager and go to their room. The manager suddenly remembers that the room rate is £25 and gives £5 to the bellboy to return to the people. On the way to the room the bellboy reasons that £5 would be difficult to share among three people so he pockets £2 and gives £1 to each person. Now each person paid £10 and got back £1. So they paid £9 each, totalling £27. The bellboy has £2, totalling £29. Where is the missing £1?
Answer:
We have to be careful what we are adding together.
Originally, they paid £30, they each received back £1, they now have only paid £27. Of this £27, £25 went to the manager for the room and £2 went to the bellboy.
Brain Puzzlers' Bog Snorkelling
Four friends were competing in the internationally renowned Brain Puzzlers' Bog Snorkelling competition. As usual, the judges were a little careless and once again, they managed to loose the results. Luckily, a number of spectators were able to remember the following snippets of information:
Only one person wore the same number as the position they finished. Gary, who didn't wear green, beat Barry. Larry beat the person who wore yellow. The person who wore number 3, wore green. The person who wore number 2 finished first whereas Harry came last. The person who finished second wore green, Barry wore yellow and the person wearing red beat the person wearing blue.
Can you work out who finished where, the number and colour they wore?
Only one person wore the same number as the position they finished. Gary, who didn't wear green, beat Barry. Larry beat the person who wore yellow. The person who wore number 3, wore green. The person who wore number 2 finished first whereas Harry came last. The person who finished second wore green, Barry wore yellow and the person wearing red beat the person wearing blue.
Can you work out who finished where, the number and colour they wore?
Answer:
# Name Wore Colour
1 Gary 2 red
2 Larry 3 green
3 Barry 1 yellow
4 Harry 4 blue
Plane and Train Spotting Contest
During a recent plane and train spotting contest, five eager entrants were lined up ready to be tested on their spotting ability. They had each spotted a number of planes (26, 86, 123, 174, 250) and a number of trains (5, 42, 45, 98, 105). From the clues below, can you determine what colour anorak each was wearing, their position, their age (21, 23, 31, 36, 40) and the number of trains and planes spotted?
1. Simon spotted 44 fewer trains than planes.
2. Keith was 36 years old.
3. The person on the far right was 8 years younger than Simon, and spotted 174 planes.
4. James was wearing a beige anorak and spotted 37 trains fewer than Simon.
5. The person who was wearing a green anorak, was 19 years younger than the person to the left of him.
6. Steven spotted 105 trains and 250 planes.
7. The person in the centre was 31 years old, was wearing a blue anorak and spotted 42 trains.
8. Alan, who was on the far left, spotted 26 planes, and spotted 72 trains more than planes.
9. The person who was wearing a red anorak, was 4 years older than Keith and was not next to the person wearing a blue anorak.
10.The person who was next to the 31 year old but not next to the person who spotted 26 planes, was wearing a orange anorak, and spotted 45 trains.
1. Simon spotted 44 fewer trains than planes.
2. Keith was 36 years old.
3. The person on the far right was 8 years younger than Simon, and spotted 174 planes.
4. James was wearing a beige anorak and spotted 37 trains fewer than Simon.
5. The person who was wearing a green anorak, was 19 years younger than the person to the left of him.
6. Steven spotted 105 trains and 250 planes.
7. The person in the centre was 31 years old, was wearing a blue anorak and spotted 42 trains.
8. Alan, who was on the far left, spotted 26 planes, and spotted 72 trains more than planes.
9. The person who was wearing a red anorak, was 4 years older than Keith and was not next to the person wearing a blue anorak.
10.The person who was next to the 31 year old but not next to the person who spotted 26 planes, was wearing a orange anorak, and spotted 45 trains.
Answer:
# Name Anorak Age Planes Trains
1 Alan red 40 26 98
2 Steven green 21 250 105
3 Simon blue 31 86 42
4 Keith orange 36 123 45
5 James beige 23 174 5
Monday, February 18, 2013
Numbers in Shapes!
In the following figure, identify the values of x and y such that:
1) The sum of numbers inside the circle must be individually higher than the heart, the diamond and the triangle.
2) The sum of numbers inside the rectangle must be half of the total of the sum of numbers inside the circle, the heart, the diamond and the triangle.
3) Both x and y should be divisible by 5.
Answer:
x = 30
y = 25
1) The sum of numbers inside the circle must be individually higher than the heart, the diamond and the triangle.
2) The sum of numbers inside the rectangle must be half of the total of the sum of numbers inside the circle, the heart, the diamond and the triangle.
3) Both x and y should be divisible by 5.
x = 30
y = 25
Who stole the cake?
During a recent police investigation, Chief Inspector Stone was interviewing five local villains to try and identify who stole Mrs Archer's cake from the mid-summers fayre. Below is a summary of their statements:
Arnold: it wasn't Edward
it was Brian
Brian: it wasn't Charlie
it wasn't Edward
Charlie: it was Edward
it wasn't Arnold
Derek: it was Charlie
it was Brian
Edward: it was Derek
it wasn't Arnold
It was well known that each suspect told exactly one lie. Can you determine who stole the cake?
Arnold: it wasn't Edward
it was Brian
Brian: it wasn't Charlie
it wasn't Edward
Charlie: it was Edward
it wasn't Arnold
Derek: it was Charlie
it was Brian
Edward: it was Derek
it wasn't Arnold
It was well known that each suspect told exactly one lie. Can you determine who stole the cake?
Answer:
Charlie committed the terrible crime.
Looking at Brian's statements, one of the statements was a lie and the other was the truth. Therefore it must have been either Charlie or Edward.
Looking at Derek's statements, for the same reason, it was either Charlie or Brian.
Therefore it must have been Charlie who committed the crime. Double checking this against the other statements confirms this.
Sunday, February 17, 2013
O = Odd, E = Even
In the following sum the digits 0 to 9 have all been used, O = Odd, E = Even, zero is even and the top row's digits add to 9. Can you determine each digit?
Answer:
Remembering that:
E + E = E
O + O = E
E + O = O
To discuss individual letters it's easiest to represent the sum as:
A B C
D E F +
--------
G H I J
The largest values for A and D are 6 and 8, which makes G = 1.
Since column 2 is E + O = O there can be no carry from column 1 (since E + O + 1 is always even). Therefore C and F are 3 and 5 (but we don't yet know which is which), therefore J = 8.
There can't be a carry from column 2 (as A + D is even) therefore E can't be 9 as this would force a carry.
Therefore I = 9. Hence B can't be 0. Therefore H = 0.
The last remaining odd number makes E = 7. Making B = 2.
Therefore A and D are 4 and 6 (but we don't yet know which is which).
Since the top row's digits have to add to 9 the top number must be 423.
This makes the sum 423 + 675 = 1098.
Rooms
Alex, Bret, Chris, Derek, Eddie, Fred, Greg, Harold, and John are nine students who live in a three storey building, with three rooms on each floor. A room in the West wing, one in the centre, and one in the East wing. If you look directly at the building, the left side is West and the right side is East. Each student is assigned exactly one room. Can you find where each of their rooms is:
1. Harold does not live on the bottom floor.
2. Fred lives directly above John and directly next to Bret (who lives in the West wing).
3. Eddie lives in the East wing and one floor higher than Fred.
4. Derek lives directly above Fred.
5. Greg lives directly above Chris.
1. Harold does not live on the bottom floor.
2. Fred lives directly above John and directly next to Bret (who lives in the West wing).
3. Eddie lives in the East wing and one floor higher than Fred.
4. Derek lives directly above Fred.
5. Greg lives directly above Chris.
Answer:
From the highest floor to lowest we have:
West Centre East
==== ====== ====
Harold Derek Eddie
Bret Fred Greg
Alex John Chris
Back to Starting Position
I have a machine which has four sequential cog wheels in constant mesh.
The largest cog has 81 teeth and the others have 52, 36 and 20 respectively.
What is the fewest number of revolutions the largest cog must make so that all of the cogs are back in their starting position?
The largest cog has 81 teeth and the others have 52, 36 and 20 respectively.
What is the fewest number of revolutions the largest cog must make so that all of the cogs are back in their starting position?
Answer:
260 revolutions.
There are a number of ways of thinking about the solution, and we find this one the quickest way to find the answer.
The total number of teeth moved by Cog 1 will be wholly divisible by each cog in turn, therefore:
Revolutions x Cog 1 ÷ Cog2 is an integer
Revolutions x Cog 1 ÷ Cog3 is an integer
Revolutions x Cog 1 ÷ Cog4 is an integer
So we are after the first number of revolutions x 81 that is an integer after division by 52, 36 and 20.
Thus:
81 81 81
-- and -- and -- all need to be integers (and not fractions).
52 36 20
An easy way to do this would be to multiply by 52 x 36 x 20 = 37,440 revolutions, which would be a correct answer, but not necessarily the smallest answer.
A better way is to break each cog down into its prime factors, where Cog 1 has the largest number of teeth:
Cog 1 - 81 = 3 x 3 x 3 x 3
Cog 2 - 52 = 2 x 2 x 13
Cog 3 - 36 = 2 x 2 x 3 x 3
Cog 4 - 20 = 2 x 2 x 5
3 x 3 x 3 x 3 and 3 x 3 x 3 x 3 and 3 x 3 x 3 x 3 and these need to be integers
------------- ------------- ------------
2 x 2 x 13 2 x 2 x 3 x 3 2 x 2 x 5
Simplifying any fraction that can be simplified gives:
3 x 3 x 3 x 3 and 3 x 3 and 3 x 3 x 3 x 3 and these need to be integers
------------- ----- -------------
2 x 2 x 13 2 x 2 2 x 2 x 5
Multiplying throughout by 2 x 2 gives:
3 x 3 x 3 x 3 and 3 x 3 and 3 x 3 x 3 x 3 and these need to be integers
------------- -------------
13 5
Multiplying throughout 13 gives:
3 x 3 x 3 x 3 and 3 x 3 x 13 and 3 x 3 x 3 x 3 x 13 and these need to be integers
------------------
5
Multiplying throughout 5 gives:
3 x 3 x 3 x 3 x 5 and 3 x 3 x 13 x 5 and 3 x 3 x 3 x 3 x 13
They are all now integers, and we have therefore multiplied by 2 x 2 x 13 x 5.
2 x 2 x 13 x 5 = 260 revolutions. As required.
The easy way from above of 37,440 is exactly 144 times this answer.
Saturday, February 16, 2013
Einstein's Puzzle
There are 5 houses in 5 different colours. In each house lives a person of a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. Using the clues below can you determine who owns the fish?
The Brit lives in a red house.
The Swede keeps dogs as pets.
The Dane drinks tea.
The green house is on the immediate left of the white house.
The green house owner drinks coffee.
The person who smokes Pall Mall rears birds.
The owner of the yellow house smokes Dunhill.
The man living in the house right in the middle drinks milk.
The Norwegian lives in the first house.
The man who smokes Blend lives next door to the one who keeps cats.
The man who keeps horses lives next door to the man who smokes Dunhill.
The owner who smokes Blue Master drinks chocolate.
The German smokes Prince.
The Norwegian lives next to the blue house.
The man who smokes Blend has a neighbour who drinks water.
The Brit lives in a red house.
The Swede keeps dogs as pets.
The Dane drinks tea.
The green house is on the immediate left of the white house.
The green house owner drinks coffee.
The person who smokes Pall Mall rears birds.
The owner of the yellow house smokes Dunhill.
The man living in the house right in the middle drinks milk.
The Norwegian lives in the first house.
The man who smokes Blend lives next door to the one who keeps cats.
The man who keeps horses lives next door to the man who smokes Dunhill.
The owner who smokes Blue Master drinks chocolate.
The German smokes Prince.
The Norwegian lives next to the blue house.
The man who smokes Blend has a neighbour who drinks water.
Answer:
The German owns the fish and the table below details the full answer:
Nationality: Norweg Dane Brit German Swede
Colour : Yellow Blue Red Green White
Beverage : water tea milk coffee chocolate
Smokes : Dunhill Blend Pall Mall Prince Blue Master
Pet : cats horses birds fish dogs
Monday, February 11, 2013
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